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0=20t-0.81t^2
We move all terms to the left:
0-(20t-0.81t^2)=0
We add all the numbers together, and all the variables
-(20t-0.81t^2)=0
We get rid of parentheses
0.81t^2-20t=0
a = 0.81; b = -20; c = 0;
Δ = b2-4ac
Δ = -202-4·0.81·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20}{2*0.81}=\frac{0}{1.62} =0 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20}{2*0.81}=\frac{40}{1.62} =24+1/1.4464285714286 $
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